okay so i created a new jsfiddle an focused on my if statments only

i managed to anser my own questions with this code

      if (latt > 0) {
      alert('posotive')
      } else {
      alert('negative')
      }

i then altered it to my needs within my script

its a shame people had to accuse me of no reasrch i just needed a chat and some help but tremdous thanks to the first commenter evolutionxbox

so first for the code so i dont upset down voters

fetch('https://geocode.xyz/london?json=1')
  .then(response => {
    if (response.ok) {
  response.json().then(data => {
  fbjson = data;
  var latt = fbjson.alt.loc.latt;
  
  var longt =fbjson.alt.loc.longt;
  
   if (latt > 0) {latt = latt +  " ° N";} else {latt = latt + " ° S"

}

   if (longt > 0) {
  longt = longt +  " ° E";
  } else {
  longt = longt + " ° W"

 }

var stringerr = latt + " / " + longt
    $div1_.textContent = stringerr;
  });
} else $div1_.textContent = 'Network response was not ok.';
})
.catch(error =>
$div1_.textContent = 'Fetch error: ' + error
);

here is the working jsfiddle for anyone needing visual help like i often do

fiddle

I have the following code which grabs the latt and longitude for london

And returns me the results 51.49742 / -0.14159

Here’s my JSFiddle
jsfiddle example

here was the original

fetch('https://geocode.xyz/london?json=1')
  .then(response => {
    if (response.ok) {
  response.json().then(data => {
  fbjson = data;
  var latt = fbjson.alt.loc.latt;
  
  var longt =fbjson.alt.loc.longt;
  var stringerr = latt + " / " + longt
      $div1_.textContent = stringerr;
    });
  } else $div1_.textContent = 'Network response was not ok.';
})
.catch(error =>
$div1_.textContent = 'Fetch error: ' + error
);

now where I am stuck is I am trying to determine n/s for latt and e/w for longt and display the result simaler to Google like this

googles results = 51.5074° N, 0.1278° W

I would like

51.5074° N / 0.1278° W

How can I determine and add
° W or others accordingly to the long and latt