Just most[0] would have fixed your code.
Changed to just track maximum count.
let As = document.getElementsByTagName('a');
let towns = new Map();
let max = [];
for(let a of As)
{
let town = a.textContent.split(',')[1].trim()
if(towns.has(town))
{
const count = towns.get(town)+1;
towns.set(town, count);
max[count] = town;
}
else
{
towns.set(town, 1);
max[1] = town;
}
}
let most = max.pop()
console.log(most);
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Bothell</a>
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Bellevue</a>
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Kirkland</a>
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Monroe</a>
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Bothell</a>
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Bothell</a>
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Bothell</a>
[...towns.entries()] is an Array of Array(2). Just pick the first element of the first element of the sorted. You don’t need the entries-part by the way, just spread the Map to an Array.
Alternatively you can use a reducer to create a frequency table, included that in te snippet.
let towns = new Map();
document.querySelectorAll('a').forEach(href => {
const town = href.textContent.split(',')[1].trim();
if(towns.has(town)) {
towns.set(town, towns.get(town)+1)
} else {
towns.set(town, 1);
}
});
const most = [...towns].sort((a, b) => b[1] - a[1])[0][0];
// ^ here
console.log(most);
// alternative use reduce to create a frequency table
const freqs = [...document.querySelectorAll('a')]
.reduce( (acc, val) => {
const town = val.textContent.split(',')[1].trim();
return {...acc, [town]: acc[town] ? acc[town] + 1 : 1 };
}, {});
// now you need entries ;)
console.log(Object.entries(freqs).sort( (a, b) => b[1] - a[1] )[0][0]);
a {display: block}
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Bothell</a>
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Bellevue</a>
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Kirkland</a>
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Monroe</a>
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Bothell</a>
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Bothell</a>
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Bothell</a>
Here is my code. The output equals “Bothell,4”. What can I do to make the output “Bothell” without the comma and count portion?
let As = document.getElementsByTagName('a');
let towns = new Map();
for(let a of As)
{
let town = a.textContent.split(',')[1].trim()
if(towns.has(town))
{
towns.set(town, towns.get(town)+1)
}
else
{
towns.set(town, 1);
}
}
let most = [...towns.entries()].sort((a, b) => b[1] - a[1])[0]
console.log(most);
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Bothell</a>
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Bellevue</a>
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Kirkland</a>
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Monroe</a>
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Bothell</a>
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Bothell</a>
<a href="/search/details/50/1/" class="address">9207 Odin Wy, Bothell</a>
Wow… it was literally just adding another[0]. Thanks so much!!
keys works as well. Thanks all!
@user120242 You are sorting on keys. Bothell being the first is a coincidence. I think OP needs the most frequent town in the collection.
@KevinBoroumand This is completely wrong. This is just subtracting the second letter of each word in the compareFunction like
