I’ve used like this. You can also use if you like this procedure.

from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions
from selenium.webdriver.common.by import By

driver = webdriver.Chrome(PATH)

css_selector = "div.abcd"
results = WebDriverWait(driver, 10).until((expected_conditions.presence_of_all_elements_located((By.CSS_SELECTOR, css_selector))))

for result in results:
    print(result.text)

I want to retrieve from a website every div class=’abcd’ element using Selenium together with ‘waiter’ and ‘XPATH’ classes from Explicit.
The source code is something like this:

<div class='abcd'>
   <a> Something </a>
</div>
<div class='abcd'>
   <a> Something else </a>
...

When I run the following code (Python) I get only ‘Something’ as a result. I’d like to iterate over every instance of the div class=’abcd’ appearing in the source code of the website.

from explicit import waiter, XPATH
from selenium import webdriver
driver = webdriver.Chrome(PATH)
result = waiter.find_element(driver, "//div[@class='abcd']/a", by=XPATH).text

Sorry if the explanation isn’t too technical, I’m only starting with webscraping. Thanks